Benchmark Test Methods for "double" Operation

JVM Tutorials - Herong's Tutorial Examples - Version 4.23, by Dr. Herong Yang

JVM Tutorials - Herong's Tutorial Examples

∟Micro Benchmark Tests on "float" and "double" Operations

∟Benchmark Test Methods for "double" Operation

This section provides a list of benchmark test methods for 'double' operations that can be called by my BenchmarkRunner.java program.

Here are my test methods for "double" operations ready to be called by my BenchmarkRunner.java program:

/**
 * BenchmarkTestDouble.java
 * Copyright (c) 2010, HerongYang.com, All Rights Reserved.
 */
class BenchmarkTestDouble {

   // The empty loop benchmark test method
   public static double emptyLoop(int steps, BenchmarkRunner runner) {
      double x = 0;
      double i = 0;
      double last = steps;
      runner.startTimer();
      for (i=0; i<last; i+=1) {
      }
      runner.stopTimer();
      x = i;
      return x;
   }

   // Test method for an assignment operation in a loop
   public static double assignment(int steps, BenchmarkRunner runner) {
      double x = 0;
      double i = 0;
      double last = steps;
      runner.startTimer();
      for (i=0; i<last; i+=1) {
         x = i;
      }
      runner.stopTimer();
      return x;
   }

   // Test method for an add operation in a loop
   public static double add(int steps, BenchmarkRunner runner) {
      double x = 0;
      double i = 0;
      double last = steps;
      runner.startTimer();
      for (i=0; i<last; i+=1) {
         x = i + 3;
      }
      runner.stopTimer();
      return x;
   }

   // Test method for a multiply operation in a loop
   public static double multiply(int steps, BenchmarkRunner runner) {
      double x = 0;
      double i = 0;
      double last = steps;
      runner.startTimer();
      for (i=0; i<last; i+=1) {
         x = i * 3;
      }
      runner.stopTimer();
      return x;
   }

   // Test method for a division operation in a loop
   public static double division(int steps, BenchmarkRunner runner) {
      double x = 0;
      double i = 0;
      double last = steps;
      runner.startTimer();
      for (i=0; i<last; i+=1) {
         x = i / 3;
      }
      runner.stopTimer();
      return x;
   }
}

Note that: